Question

A traction wheel having 600 mm diameter was tested in a soil bin and following data was obtained, angular speed=10rpm, input torque to wheel angle=60 Nm, drawbar pull=150 N, normal load on wheel axle=500 N, wheel forward speed=0.25 ms^-1. What will be the slippage?

(a) 19.47%

(b) 20.18%

(c) 20.43%

(d) 19.98%

The question was posed to me in class test.

My query is from Traction and Traction Theory topic in division Farm Tractor of Farm Machinery

Answer 1

The correct choice is (c) 20.43%

To explain: μ = P/R2 = 150/500 = 0.3

Vt = \(\frac{0.6}{2}*\frac{2π*10}{60*10}\) = 0.3142 ms^-1

Slippage = \(\frac{0.3142-0.25}{0.3142}\)*100 = 20.43%