Question

A diesel engine transmits 25 KW at the end of the crankshaft, moving at 1650 rev/min, find the torque exerted by the piston.

(a) 148.90 Newton-metre

(b) 144.75 Newton-metre

(c) 150.75 Newton-metre

(d) 120.10 Newton-metre

I have been asked this question in an interview for internship.

Asked question is from Diesel Engine Vs. Petrol Engine topic in section Internal Combustion Engine of Farm Machinery

Answer 1

The correct option is (b) 144.75 Newton-metre

To elaborate: Power(W) = \(\frac{2πnT}{60}\)

25*1000=\(\frac{2π*1650*T}{60}\)

T=144.75 Newton-metre.