Question

A cylinder can withstand the L.P.G. at 16.7 atmospheric pressure, if at any time instant the inside pressure of L.P.G. becomes 13 atmosphere pressures at 27°C. Then what will be the temperature at which it will explode?

(a) 116.7°C

(b) 114.1°C

(c) 112.1°C

(d) 111.6°C

I had been asked this question during an interview.

This question is from Diesel Engine Vs. Petrol Engine topic in division Internal Combustion Engine of Farm Machinery

Answer 1

Right answer is (c) 112.1°C

To explain: Since volume of cylinder remains constant, hence using the formula

\(\frac{P1}{T1}=\frac{P2}{T2}\)

\(\frac{16.7}{T1}=\frac{13}{300} \)

T1 = 385.3K

T1 = 112.1°C.