The correct answer is (d) 18.98 KW
To explain I would say: Integrated power = \((\frac{pLAN}{60,000})\)*n/2
= \(\frac{7*105*0.12*\frac{π}{4}*(0.1)2*2000*4}{60000*2}\)
= 43.98 KW
Brake power = Integrated power – Frictional power
= 43.98-25
= 18.98 KW.