Question

A diesel tractor develops 60 KW with a coolant temperature difference 5.5°C. What will be the quantity of water to be circulated through the radiator?

(a) 3.72 l/s

(b) 5.56 l/s

(c) 9.88 l/s

(d) 11.10 l/s

This question was posed to me in my homework.

I'd like to ask this question from Cooling System topic in portion Fuel Supply and Cooling System of Farm Machinery

Answer 1

Correct option is (b) 5.56 l/s

To explain I would say: In tractors, the required flow rate of water is 0.16 l/s per kw to drop the radiator temperature from 5.5 to 8.5°C

Q = 60*0.58*0.16 l/s = 5.56 lps