Question

What would be the quantity of water to be circulated through the radiator, if diesel tractor developed 40 KW with a coolant temperature difference of 5.5°C?

(a) 4.26 lps

(b) 4.19 lps

(c) 2.86 lps

(d) 3.72 lps

This question was addressed to me in an online interview.

The query is from Cooling System topic in section Fuel Supply and Cooling System of Farm Machinery

Answer 1

Right choice is (d) 3.72 lps

The explanation is: In tractors, the required flow rate of water is 0.16 l/s per kw to drop the radiator temperature from 5.5 to 8.5°C

Q = 40*0.58*0.16 l/s = 3.72 lps