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In Darlington pair differential amplifier the current gain is given as 100. Where IB1=5µA and IC1=0.35mA. Determine IC2

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in Linear Integrated Circuits by (37.1k points)
In Darlington pair differential amplifier the current gain is given as 100. Where IB1=5µA and IC1=0.35mA. Determine IC2

(a) 0.5mA

(b) 1.5mA

(c) 2mA

(d) 0.15mA

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Asked question is from Operational Amplifier Internal Circuit topic in portion Operational Amplifier of Linear Integrated Circuits

1 Answer

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by (39.8k points)
The accurate choice is (d) 0.15mA

Simplify with an easy explanation: The current gain in Darlington pair differential amplifier is given as β=( IC1+IC2)/IB1.

Substituting the values in the equation, we get

IC2=(β×IB1)-IC1 =(100×5µA)-0.35mA =0.15mA.

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