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What is the equation of load current for a differential amplifier with an active load?

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+1 vote
in Linear Integrated Circuits by (37.1k points)
What is the equation of load current for a differential amplifier with an active load?

(a) IL = gm×vd

(b) IL = Iq /2

(c) IL = β×Iq×( Vin1 – Vin2)

(d) IL = 2×gm/( Vin1 – Vin2)

This question was addressed to me in exam.

My doubt stems from Operational Amplifier Internal Circuit topic in portion Operational Amplifier of Linear Integrated Circuits

1 Answer

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by (39.8k points)
The correct option is (a) IL = gm×vd

Expand on the concept with: The load current is given as product of difference between input & output voltage and transconductance. Therefore, the equation of load current is ,

IL = gm×vd.

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