Ask a Question

The input voltage of a difference amplifier are 2.5v and 4.9v. If the transconductance is 0.065Ω^-1, determine the load current entering the next stage

← Prev Question Next Question →
+1 vote
in Linear Integrated Circuits by (38.2k points)
The input voltage of a difference amplifier are 2.5v and 4.9v. If the transconductance is 0.065Ω^-1, determine the load current entering the next stage

(a) 0.156A

(b) 1.56A

(c) 0.156mA

(d) 15.6µA

I had been asked this question during an interview.

This interesting question is from Operational Amplifier Internal Circuit in division Operational Amplifier of Linear Integrated Circuits

1 Answer

0 votes
by (39.8k points)
Accurate answer is (a) 0.156A

Discover the easiest explanation: Load current entering the next stages of amplifier is the sum of individual load current, which is given by IL = IL1+ IL2 (Since only two input voltages are given).

IL = gm×Vin1 + gm×Vin2

= gm×( Vin1 – Vin2) = 0.065 Ω^-1×(4.9v-2.5v) = 0.156A.

Related questions

We welcome you to Carrieradda QnA with open heart. Our small community of enthusiastic learners are very helpful and supportive. Here on this platform you can ask questions and receive answers from other members of the community. We also monitor posted questions and answers periodically to maintain the quality and integrity of the platform. Hope you will join our beautiful community

Categories

Powered by TalkJarvis
...