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The input voltage of a difference amplifier are 2.5v and 4.9v. If the transconductance is 0.065Ω^-1, determine the load current entering the next stage

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in Linear Integrated Circuits by (37.1k points)
The input voltage of a difference amplifier are 2.5v and 4.9v. If the transconductance is 0.065Ω^-1, determine the load current entering the next stage

(a) 0.156A

(b) 1.56A

(c) 0.156mA

(d) 15.6µA

I had been asked this question during an interview.

This interesting question is from Operational Amplifier Internal Circuit in division Operational Amplifier of Linear Integrated Circuits

1 Answer

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by (39.8k points)
Accurate answer is (a) 0.156A

Discover the easiest explanation: Load current entering the next stages of amplifier is the sum of individual load current, which is given by IL = IL1+ IL2 (Since only two input voltages are given).

IL = gm×Vin1 + gm×Vin2

= gm×( Vin1 – Vin2) = 0.065 Ω^-1×(4.9v-2.5v) = 0.156A.

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