+1 vote
in Machine Kinematics by (38.0k points)
The speed of driving shaft of a Hooke’s Joint of angle 19.5^0 is 500 r.p.m. The maximum speed of the driven shaft is nearly

(a) 168 r.p.m.

(b) 444 r.p.m.

(c) 471 r.p.m.

(d) 531 r.p.m.

The question was posed to me during an online exam.

Question is from Acceleration of a Point on a Link topic in portion Acceleration in Mechanisms of Machine Kinematics

1 Answer

0 votes
by (106k points)
The correct choice is (d) 531 r.p.m.

The best I can explain: Nmax = N/cosα = 500/cos19.5^0 = 531 r.p.m.

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