+1 vote
in Machine Kinematics by (38.0k points)
The maximum velocity of the driven shaft of a Hooke’s joint is

(a) ω1 cosα

(b) ω1/cosα

(c) ω1 sinα

(d) ω1/sinα

The question was posed to me in a job interview.

Enquiry is from Mechanisms with Lower Pairs topic in section Mechanisms with Lower Pairs of Machine Kinematics

1 Answer

0 votes
by (106k points)
Correct choice is (b) ω1/cosα

The explanation is: Maximum speed of the driven shaft,

ω1(max) = ωcosα/ 1 – sin^2α = ωcosα/cos^2α = ω/cosα.

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