Question

The equivalent length of a simple pendulum which gives the same frequency as the compound pendulum is

(a) h/ k^2G +h^2

(b) k^2G +h^2/h

(c) h^2/k^2G +h^2

(d) k^2G +h^2/h^2

The question was posed to me during a job interview.

This interesting question is from Simple Harmonic Motion in portion Simple Harmonic Motion of Machine Kinematics

Answer 1

Right option is (b) k^2G +h^2/h

Explanation: By comparing the frequencies of simple pendulum to compound pendulum we get the equivalent length of simple pendulum as k^2G +h^2/h.