Question

The frequency of oscillation of a compound pendulum is

(a) 1/2π √g.h/k^2G +h^2

(b) 1/2π √k^2G +h^2/g.h

(c) 2π√g.h/k^2G +h^2

(d) 2π√k^2G +h^2/g.h

I had been asked this question in a job interview.

My question is taken from Simple Harmonic Motion in division Simple Harmonic Motion of Machine Kinematics

Answer 1

Correct answer is (a) 1/2π √g.h/k^2G +h^2

The best explanation: We know that the periodic time,

              tp = 2π√Displacement/Accleration = 2π√θ/α

  and frequency of oscillation,n = 1/tp = 1/2π √g.h/k^2G +h^2

where kG = Radius of gyration about the centroidal axis, and

h = Distance between the point of suspension and centre of gravity of the body.