Question

A motor has a wheel base of 2.73 m and pivot centre of 1.065 m. the rear and front wheel track is 1.217 m. calculate turning circle radius of the outer front and inner rear wheels when the angle of inside lock is 40° and outside lock is 32°.

(a) 7.25 m:4.18 m

(b) 6.25 m: 2.18 m

(c) 5.25 m: 3.18 m

(d) 4.25 m: 1.18 m

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This intriguing question originated from Tractor Tyre and Front Axle topic in division Farm Tractor of Farm Machinery

Answer 1

Correct option is (c) 5.25 m: 3.18 m

Explanation: Rf = \(\frac{b}{sin⁡φ}+\frac{a-c}{2}=\frac{2.743}{sin⁡32}+\frac{1.217-1.065}{2}\) = 5.25 m

Turning radius of inner radius wheel Rr = b cot φ – (a-c)/2 = 3.18 m.