+1 vote
in Machine Kinematics by (38.0k points)
If the angle of wrap on smaller pulley of diameter 250 mm is 120^0 and diameter of larger pulley is twice the diameter of smaller pulley, then the centre distance between the pulleys for an open belt drive is

(a) 1000 mm

(b) 750 mm

(c) 500 mm

(d) 250 mm

The question was asked in an online interview.

My doubt is from Pulleys topic in division Belt, Rope and Chain Drives of Machine Kinematics

1 Answer

0 votes
by (106k points)
Correct option is (d) 250 mm

Best explanation: sin α = (D -d)/2c

Angle of wrap on smaller pulley = п – 2α

2п/3 =  п – 2sin^-1(D -d)/2c

c = 250 mm.

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