If the angle of wrap on smaller pulley of diameter 250 mm is 120^0 and diameter of larger pulley is twice the diameter of smaller pulley, then the centre distance between the pulleys for an open belt drive is

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If the angle of wrap on smaller pulley of diameter 250 mm is 120^0 and diameter of larger pulley is twice the diameter of smaller pulley, then the centre distance between the pulleys for an open belt drive is

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Greg · Answer 1 · 2022-10-20T04:51:06+0000

Correct option is (d) 250 mm

Best explanation: sin α = (D -d)/2c

Angle of wrap on smaller pulley = п – 2α

2п/3 = п – 2sin^-1(D -d)/2c

c = 250 mm.

If the angle of wrap on smaller pulley of diameter 250 mm is 120^0 and diameter of larger pulley is twice the diameter of smaller pulley, then the centre distance between the pulleys for an open belt drive is

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