Right option is (c) 66.66%
To explain: Given, load raised, W = 360 N
Effort applied, P = 60 N
Distance moved by the effort, y = 1.8 m
Distance moved by the load, x = 200 mm = 0.2 m
Mechanical advantage, M.A. = W/P = 360/60 = 6
Velocity ratio, V.R. = y/x = 1.8/0.2 = 9
Efficiency at the load, ȵ = M.A./V.R. x 100 = 6/9 x 100 = 66.66%.