+1 vote
in Machine Kinematics by (38.0k points)
A machine raised a load of 360 N through a distance of 200 mm. The effort, a force of 60 N moved 1.8 m during the process. Calculate velocity ratio.

(a) 6

(b) 7

(c) 8

(d) 9

I got this question in semester exam.

I'd like to ask this question from Relative Velocity of Two Bodies Moving in Straight Lines in section Velocity in Mechanisms of Machine Kinematics

1 Answer

0 votes
by (106k points)
The correct option is (d) 9

Explanation: Given, load raised, W = 360 N

Effort applied, P = 60 N

Distance moved by the effort, y = 1.8 m

Distance moved by the load, x = 200 mm = 0.2 m

Velocity ratio, V.R. = y/x = 1.8/0.2 = 9.

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