+1 vote
in Machine Dynamics by (34.3k points)
For a multicylinder engine, the moment of inertia of a flywheel is 6500 kg-m^2, from the turning moment diagram, it is found that fluctuation of energy is 56000 N-m, if mean speed is 120 rpm, then find maximum speed.

(a) 121

(b) 119

(c) 122

(d) 118

This question was addressed to me during an online interview.

I'm obligated to ask this question of Turning Moment Diagram for a Multicylinder Engine in division Turning Moment Diagrams and Flywheel of Machine Dynamics

1 Answer

0 votes
by (38.6k points)
The correct option is (a) 121

The explanation is: We know that ΔE= I ω^2. Cs

= I ω. (ω1-ω2)

= 6500. 120x(2π/60)^2(N1-N2)

N1-N2 = 2

N=120

Therefore, N1=121.

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