+1 vote
in Machine Dynamics by (34.3k points)
The speed of an engine varies from 210 rad/s to 190 rad/s. During the cycle the change in kinetic energy is found to be 400 Nm. The inertia of the flywheel in kg/m2 is

(a) 0.10

(b) 0.20

(c) 0.30

(d) 0.40

The question was asked in an interview.

The origin of the question is Flywheel in division Turning Moment Diagrams and Flywheel of Machine Dynamics

1 Answer

0 votes
by (38.6k points)
The correct choice is (a) 0.10

The best I can explain: Given ω1 = 210 rad/ sec, ω2 = 190 rad/ sec, ΔE= 400 Nm

As the speed of flywheel changes from ω1 to ω2, the maximum fluctuation of energy,

ΔE = 1/2I [(ω1)^2 (ω2)^2]

I = 0.10 kgm^2

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