Find the activated diffusivity of carbon if energy of activation is 6 kJ; the value of constant diffusivity is 2.5 sq.m/sec. (Hint: the value of exponential of (-6/RT) is 2.55)

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Find the activated diffusivity of carbon if energy of activation is 6 kJ; the value of constant diffusivity is 2.5 sq.m/sec. (Hint: the value of exponential of (-6/RT) is 2.55)

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Chris · Answer 1 · 2022-10-12T08:04:45+0000

Correct option is (a) 6.375 sq.m/s

Easy explanation: Activated diffusivity= constant diffusivity * exponential value

= 2.5 * 2.55

= 6.375.

Find the activated diffusivity of carbon if energy of activation is 6 kJ; the value of constant diffusivity is 2.5 sq.m/sec. (Hint: the value of exponential of (-6/RT) is 2.55)

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