+1 vote
in Farm Machinery by (38.9k points)
An IC engine consumes high speed diesel oil at the rate of 0.5 kg/h. Calculate the power of the engine.

(a) 10 KW

(b) 15.45 KW

(c) 6.15 KW

(d) 22.15 KW

The question was asked during an online interview.

The origin of the question is Fuel Supply System in Ignition or Diesel Engine in chapter Ignition and Power Transmission of Farm Machinery

1 Answer

+2 votes
by (243k points)
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Best answer
Right option is (c) 6.15 KW

The explanation: Heat volume = mass flow rate of fuel * calorific value = 0.5*10550 = 5275 kcal/hr

5275 kcal/h = 5275*4.2 k joules/hr = \(\frac{5275*4.2*1000}{6154.167} \)

Power of engine = 6.15 KW.

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