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If centre distance for a chain drive is 750mm with number of teeth on the driving and driven sprockets being 40 and 20 respectively, then calculate the number of links required. Given: Pitch is taken as 19mm.

(a) 112

(b) 110

(c) 111

(d) 109

I was questioned about this in a dream while sleeping.

I am studying the Design of Chain Drive topic in Friction Clutches, Brakes, Belt Drives and Chain Drives of Machine Design

1 Answer

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by (52.6k points)
Best answer is (b) 110

To make it clear: 2(a/p) + (z₁+z₂)/2 +( z₂- z₁/2π)²xp/a.

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