To determine the maximum input signal to avoid distortion in the output of an inverting amplifier, we need to consider the gain of the amplifier and the maximum output amplitude.
Given:
- The gain of the amplifier A=50A = 50A=50
- Maximum output amplitude Vout=4.2VV_{out} = 4.2VVout=4.2V
The maximum input signal Vin(max)V_{in(max)}Vin(max) can be determined using the following relationship for an inverting amplifier:
Vout=−A×VinV_{out} = - A \times V_{in}Vout=−A×Vin
Solving for VinV_{in}Vin:
Vin(max)=VoutAV_{in(max)} = \frac{V_{out}}{A}Vin(max)=AVout
Substituting the values:
Vin(max)=4.2V50=0.084V=84mVV_{in(max)} = \frac{4.2V}{50} = 0.084V = 84mVVin(max)=504.2V=0.084V=84mV
However, this value is close to the options provided, so it seems there may be a misunderstanding. The provided options do not match exactly, but the closest correct answer is:
None of the listed options are an exact match, but based on the calculation, 84mV would be the correct value. Please check the problem again for any further constraints or rounding assumptions.