+1 vote
in Irrigation Engineering by (75.2k points)
Calculate the maximum shear-stress induced if the horizontal average shear stress induced in u/s portion of the dam at the base is 36.45 kN/m^2.

(a) 43.74 kN/m^2

(b) 47.38 kN/m^2

(c) 51.03 kN/m^2

(d) 54.67 kN/m^2

The question was asked during an online exam.

My question is from Stability of Earthen Slopes in portion Earthen and Rock Fill Dams of Irrigation Engineering

1 Answer

0 votes
by (106k points)
Right choice is (c) 51.03 kN/m^2

Best explanation: By Photoelastic studies, the maximum intensity of shear stress is equal to 1.4 times the average shear intensity at a distance 0.6 B from the heel.

Ꞇmax = 1.4 Ꞇavg = 1.4 x 36.45 = 51.03 kN/m^2.

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