The correct answer is (b) Q = Cd x A x \(\sqrt{2gH_L}\)
The explanation is: After knowing the velocity through the pipe, we can calculate discharge using the relation discharge = velocity x area. Mathematically q = V x A, therefore q = Cd x A x \(\sqrt{2gH_L}\) where q = discharge, Cd = coefficient of friction, A = area of pipe, HL = difference of head between FSL of distributary and FSL of water course.