+1 vote
in Machine Kinematics by (38.0k points)
If the drive efficiency is 80%, then torque required on the input shaft to create 1000 N output thrust is

(a) 20 Nm

(b) 25 Nm

(c) 32 Nm

(d) 50 Nm

I got this question by my college professor while I was bunking the class.

The above asked question is from Standard Spur Gears topic in division Toothed Gearing & Gear Trains of Machine Kinematics

1 Answer

0 votes
by (106k points)
Right answer is (b) 25 Nm

The explanation: Module m = 2,

D/T = 2

∴ D = 80 × 2 = 160 mm

 2F = 1000, or F = 500 N

Let T1 be the torque applied by motor.

TT2 be the torque applied by gear.

∴ Power transmission = 80%

Now, T1ω12 x ω2/0.8

T1 = 25 N-m.

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