+1 vote
in Machine Kinematics by (38.0k points)
The frictional torque transmitted in a conical pivot bearing, considering uniform wear, is

(a) 1/2 × μ.W. R cosec α

(b) 2/3 × μ.W. R cosec α

(c) 3/4 × μ.W. R cosec α

(d) μ.W.R cosec α

This question was posed to me by my college professor while I was bunking the class.

The question is from Friction and Double Hooke’s Joint in portion Friction of Machine Kinematics

1 Answer

0 votes
by (106k points)
Right choice is (a) 1/2 × μ.W. R cosec α

To explain I would say: Total frictional torqur = 1/2 × μ.W. R cosec α

where R = Radius of the shaft, and

      α = Semi-angle of the cone.

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