Right option is (b) 0.8 rad/s^2
The explanation is: Given : k = 1 m ; m = 2500 kg ; T = 1500 N-m
Angular acceleration of the flywheel
Let α = Angular acceleration of the flywheel.
We know that mass moment of inertia of the flywheel,
I=m.k^2 = 2500×12 = 2500 kg-m^2
We also know that torque ( T ),
1500 = I .α = 2500 × α
or α = 1500 / 2500 = 0.6 rad/s^2