Right answer is (b) \(z_0=\frac{2c}{γ} \frac{1}{√K_a } \)
The explanation: The tension at the top level of retaining wall reduces to zero at a depth,
\(z_0=\frac{2c tanα}{γ}, \)
Since, \(K_a=\frac{1}{tan^2 (45°+\frac{φ}{2})}, \)
∴ \(z_0=\frac{2c}{γ} \frac{1}{√K_a}. \)