The correct answer is (c) \(\frac{∂σ_r}{∂r}+\frac{1}{r} \frac{∂τ_{rθ}}{∂θ}+\frac{σ_r-σ_θ}{r}=0\)
Explanation: The equilibrium equations in polar coordinates are given by,
1. \(\frac{∂σ_r}{∂r}+\frac{1}{r} \frac{∂τ_{rθ}}{∂θ}+\frac{σ_r-σ_θ}{r}=0 \)
2. \(\frac{1}{r}\frac{∂σ_θ}{∂θ}+\frac{∂τ_{rθ}}{∂r}+\frac{2τ_{rθ}}{r}=0.\)