+1 vote
in Geotechnical Engineering I by (102k points)
The normal stress in x-direction in terms of effective stress is given by __________

(a) σx= σx’+γw(h-he)

(b) σx= σx’*γw(h-he)

(c) σx= σx’-γw(h-he)

(d) σx= σx’

I had been asked this question in an online quiz.

I want to ask this question from Elasticity in section Elements of Elasticity of Geotechnical Engineering I

1 Answer

+1 vote
by (727k points)
selected by
 
Best answer
The correct choice is (a) σx= σx’+γw(h-he)

For explanation I would say: The total stress is equal to effective stress plus pore pressure. In x- direction, the normal stress is given by,

σx= σx’+u

u= γw(h-he)

where, h=total head at the point

he=elevation head

∴ σx= σx’+γw(h-he).

Related questions

We welcome you to Carrieradda QnA with open heart. Our small community of enthusiastic learners are very helpful and supportive. Here on this platform you can ask questions and receive answers from other members of the community. We also monitor posted questions and answers periodically to maintain the quality and integrity of the platform. Hope you will join our beautiful community
...