Question

How can we write kinematic viscosity using the MLT system?

(a) [M][L][T]^-2

(b) [M]^0[L]^2[T]^-1

(c) [M][L]^-1[T]^-1

(d) [M][L][T]^3

The question was asked in class test.

My question is from Dimensional Homogenity topic in chapter Dimensional and Model Analysis of Fluid Mechanics

Answer 1

Correct option is (b) [M]^0[L]^2[T]^-1

Explanation: Kinematic viscosity can be written dimensionally by [M]0[L]2[T]^-1. This is by adopting the basic SI or MKS units. Where, [M] is the mass, [L] is the length and [T] is the time. Thus, the correct option is [M]^0[L]^2[T]^-1.