Question

How can we write momentum using the MLT system?

(a) [M][L][T]^-2

(b) [M]^0[L]^2[T]^-1

(c) [M][L][T]^-1

(d) [M][L][T]^3

The question was asked in my homework.

My doubt stems from Dimensional Homogenity in division Dimensional and Model Analysis of Fluid Mechanics

Answer 1

The correct answer is (c) [M][L][T]^-1

The best I can explain: Momentum can be written dimensionally by [M][L][T]^-1. This is by adopting the basic SI or MKS units. Where, [M] is the mass, [L] is the length and [T] is the time. Thus, the correct option is [M][L][T]^-1.