Correct answer is (d) Ra =4kΩ ; Rb= 10kΩ
Simply put: We know that input offset voltage, Vio =(Rc*Vmax)/ Rb
=> Rb = Vmax*(Rc / Rb ) = (10v/10mv)*10Ω (∵ Vio specified on the datasheet is 10mv for LM307 op-amp).
=> Rb =10000 = 10kΩ.
Since Rb > Rmax let us choose Rb = 10*Rmax. (Where Rmax = Ra/4).
∴ Rb = (10*Rb)/4 and Ra = Rb/2.5 = 10kΩ/2.5=4kΩ.