Right answer is (a) \(k=\frac{q}{2πh}log_{10} \frac{L}{r}\)
The explanation is: The coefficient of permeability k for L ≥ 10r is given by,
\(k=\frac{q}{2πLh}log_{10} \frac{L}{r}\)
where, q=discharge or constant rate of flow
r=radius of casing
h=differential head of water
L=length of portion of hole tested.