Question

Which of the following is the expression of the Rose equation where symbols have their usual meanings?

(a) hf  = f* (L/(s *d)) * ((1-e) /e^3) * (v^2/g)

(b) hf  = f* (L/(s *d)) * ((1-e) /e^3) * (v/g)

(c) hf  = f* (L/(s *d)) * ((1-e) /e^4) * (v^2/g)

(d) hf  = f* (L/(s *d)) * ((1-e) /e^2) * (v^2/g)

I have been asked this question in exam.

My question is based upon Filtration Hydraulics topic in division Filtration of Environmental Engineering

Answer 1

Correct option is (a) hf  = f* (L/(s *d)) * ((1-e) /e^3) * (v^2/g)

For explanation I would say: The expression of the Rose equation is given by  hf  = f* (L/(s *d)) * ((1-e^4) /e^3) * (v^2/g) where  hf = head loss, d = diameter of pipe. L = length of pipe and v=approach velocity and  f = 1.067CD, Where CD  is the coefficient of drag.