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A machine vice whose length of the handle is 150mm and the coefficient of friction for thread and collar are 0.15 and 0.17 respectively has a force applied at handle of 125N. Also the outer and inner diameters of collar are 55mm and 45mm respectively. Find the clamping force W if nominal diameter=22mm and pitch=5mm.

(a) 4539.45N

(b) 2868.73N

(c) 3657.56N

(d) 2134.34N

I was tested on this by my college professor while I was bunking the class.

This challenging question is from the Power Screws Numericals topic in unit Threaded Joints of Machine Design

1 Answer

0 votes
ago by (48.2k points)
The recommended answer is (b) 2868.73N

Let me elaborate: Net torque=M₁+M₂ or 125 x 150=2.286W + 4.25W or W=2868.73N.

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