The correct choice is (d) 0.128 kN/m^2
Easy explanation: Given,
Z=4m
Q=20 kN
r=1
The Boussinesq’s shear stress τrz is given by,
\(τ_{rz}=\frac{3Qr}{2πz^3}\left[\frac{1}{1+(\frac{r}{z})^2}\right]^{\frac{5}{2}} \)
∴ \(τ_{rz}=\frac{3*20*1}{2π4^3}\left[\frac{1}{1+(\frac{1}{4})^2}\right]^{\frac{5}{2}} \)
∴ τrz=0.128 kN/m^2.