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The proportional depth of a circular sewer running partially half is __________

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+1 vote
in Environmental Engineering by (81.4k points)
The proportional depth of a circular sewer running partially half is __________

(a) (1-cosK/2)

(b) (1/2) * (1-sinK/2)

(c) (1/2) * (1-cosK/2)

(d) (1-cosK/2)^2

This question was posed to me during an online interview.

My query is from Hydraulic Elements of Circular Sewers topic in portion Hydraulic Design of Sewers of Environmental Engineering

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Best answer
The correct option is (c) (1/2) * (1-cosK/2)

Explanation: Depth of flow d = (D/2) * (1-cosK/2)

Proportional depth = Depth of flow d / Diameter of section D = (D/2) * (1-cosK/2) / D

                = (1/2) * (1-cosK/2).

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